(3y-1)(2y^3+4y^2-3)=

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Solution for (3y-1)(2y^3+4y^2-3)= equation: 


Simplifying
(3y + -1)(2y3 + 4y2 + -3) = 0

Reorder the terms:
(-1 + 3y)(2y3 + 4y2 + -3) = 0

Reorder the terms:
(-1 + 3y)(-3 + 4y2 + 2y3) = 0

Multiply (-1 + 3y) * (-3 + 4y2 + 2y3)
(-1(-3 + 4y2 + 2y3) + 3y * (-3 + 4y2 + 2y3)) = 0
((-3 * -1 + 4y2 * -1 + 2y3 * -1) + 3y * (-3 + 4y2 + 2y3)) = 0
((3 + -4y2 + -2y3) + 3y * (-3 + 4y2 + 2y3)) = 0
(3 + -4y2 + -2y3 + (-3 * 3y + 4y2 * 3y + 2y3 * 3y)) = 0
(3 + -4y2 + -2y3 + (-9y + 12y3 + 6y4)) = 0

Reorder the terms:
(3 + -9y + -4y2 + -2y3 + 12y3 + 6y4) = 0

Combine like terms: -2y3 + 12y3 = 10y3
(3 + -9y + -4y2 + 10y3 + 6y4) = 0

Solving
3 + -9y + -4y2 + 10y3 + 6y4 = 0

Solving for variable 'y'.

The solution to this equation could not be determined.

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